L^2+4L=320

Solution for L^2+4L=320 equation:

Simplifying
L2 + 4L = 320

Reorder the terms:
4L + L2 = 320

Solving
4L + L2 = 320

Solving for variable 'L'.

Reorder the terms:
-320 + 4L + L2 = 320 + -320

Combine like terms: 320 + -320 = 0
-320 + 4L + L2 = 0

Factor a trinomial.
(-20 + -1L)(16 + -1L) = 0

Subproblem 1
Set the factor '(-20 + -1L)' equal to zero and attempt to solve:

Simplifying
-20 + -1L = 0

Solving
-20 + -1L = 0

Move all terms containing L to the left, all other terms to the right.

Add '20' to each side of the equation.
-20 + 20 + -1L = 0 + 20

Combine like terms: -20 + 20 = 0
0 + -1L = 0 + 20
-1L = 0 + 20

Combine like terms: 0 + 20 = 20
-1L = 20

Divide each side by '-1'.
L = -20

Simplifying
L = -20
Subproblem 2
Set the factor '(16 + -1L)' equal to zero and attempt to solve:

Simplifying
16 + -1L = 0

Solving
16 + -1L = 0

Move all terms containing L to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -16 + -1L = 0 + -16

Combine like terms: 16 + -16 = 0
0 + -1L = 0 + -16
-1L = 0 + -16

Combine like terms: 0 + -16 = -16
-1L = -16

Divide each side by '-1'.
L = 16

Simplifying
L = 16
Solution
L = {-20, 16}